(3z)^(1/2)((6z)^(5/3))^(-5/2)

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Solution for (3z)^(1/2)((6z)^(5/3))^(-5/2) equation: 


D( z )

3*z < 0

(6*z)^(5/3) < 0

(6*z)^(5/3) = 0

3*z < 0

3*z < 0

3*z+0 < 0 // - 0

3*z < 0 // : 3

z < 0/3

z < 0

(6*z)^(5/3) < 0

(6*z)^(5/3) < 0

6^(5/3)*z^(5/3) < 0

6^(5/3)*z^(5/3) < 0 // : 6^(5/3)

z^(5/3) < 0/(6^(5/3))

z^(5/3) < 0

z >= 0

z belongs to the empty set

(6*z)^(5/3) = 0

(6*z)^(5/3) = 0

6^(5/3)*z^(5/3) = 0 // : 6^(5/3)

z^(5/3) = 0

z = 0

z in (0:+oo)

((6*z)^(5/3))^(-5/2)*(3*z)^(1/2) = 0

6^(-25/6)*3^(1/2)*z^(-11/3) = 0 // : 6^(-25/6)*3^(1/2)

z^(-11/3) = 0

z naleu017Cy do O

z belongs to the empty set

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